如图四棱锥p Abcd中侧面pad为等边三角形且垂直于底面abcdab=bc=$frac{1}{2}$ad∠bad=∠abc=90 Sketch Coloring Page

如图四棱锥p Abcd中侧面pad为等边三角形且垂直于底面abcdab=bc=$frac{1}{2}$ad∠bad=∠abc=90 Template

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anonymous

anonymous
sketch #4436 Bob Marley by Luiza Irma

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anonymous
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anonymous
sketch #3339 Sasuke by Jean-Benoit Renaud

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sketchmaster
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sketch #1169 ENJOY IT!!!!!!!! OH NO EAT IT OR IT WILL MELT!!!!! :0

anonymous

anonymous
sketch #1169 ENJOY IT!!!!!!!! OH NO EAT IT OR IT WILL MELT!!!!! :0

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anonymous
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anonymous
sketch #5162 Alien by KiNg Buamir

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anonymous
sketch #5278 Cosmos by Jenna Khoùlix�

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anonymous
sketch #3686 Toy Story by Thania Arruda

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anonymous
sketch #5150 Regina from Dino Crisis by Hsien-Ying Hsieh

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Amer Amimer
sketch #2813 Stan from South Park by Amer Amimer

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sketch #3310 Link by Cxsar Alvarez

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anonymous
sketch #4883 White tiger by Kayson Danielle

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anonymous
sketch #4682 Elvis Presley by Nassim Nouri

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anonymous
sketch #3774 Marilyn Manson by Junior Silva

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anonymous

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sketch #5191 The View by Vicente Vera

sketch #2644 Purple bun

Rachel Roe
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tomski如图四棱锥p abcd中侧面pad为等边三角形且垂直于底面abcdab=bc=$frac{1}{2}$ad∠bad=∠abc=90 coloring

如图在四棱锥P ABCD中PA⊥平面ABCD底面ABCD为平行四边形且AB=1BC=2EF分别为ADBC的中点．I求证 sketch template

如图在四棱锥P ABCD中侧面底面ABCD底面ABCD是菱形侧面PAD是等边三角形且PB与面PAD所成角为1求四棱锥P sketch template

$如图四棱锥P ABCD中侧面PAD为等边三角形且垂直于底面ABCDAB=BC=$frac{1}{2}$AD∠BAD=∠ABC=90 sketch template$

如图四棱锥P ABCD的底面ABCD为一直角梯形侧面PAD是等边三角形其中BA⊥ADCD⊥ADCD=2AD=2AB=2平面PAD⊥ sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

如图在四棱锥P—ABCD中PA⊥底面ABCDAB⊥ADAC⊥CD∠ABC=60°PA=AB=BCE是PC的中点1证明AE sketch template

如图，在四棱锥P ABCD中，底面ABCD是平行四边形，∠BCD=120°，侧面PAB⊥底面ABCD，PB=2√6，AB=AC=PA=2√3 sketch template

如图在四棱锥P ABCD中PA⊥底面ABCDAB⊥ADBC∥ADPA=AB=BC=2AD=4．1求四棱锥P ABCD的体积2 sketch template

18．如图在四棱锥P ABCD中侧面PAD⊥底面ABCD侧棱PA＝PD=底面ABCD为直角梯形其中BC∥ADAB⊥ADAD sketch template

如图四棱锥P ABCD中PD⊥平面ABCDPD=DC=BC=1AB=2AB∥DC∠BCD=900 1求证PC⊥BC 2求 sketch template

如图，在四棱锥P ABCD中，侧面PAD⊥ 底面ABCD，侧棱PA=PD=√2，底面ABCD为直角梯形，其中BC//AD，AB⊥ AD，AD sketch template

如图在四棱锥P ABCD中底面ABCD是正方形侧面PAD⊥底面ABCD且PA⊥PDEF分别为PCBD的中点．证明1EF∥平面 sketch template

如图四棱锥P ABCD中PD⊥平面ABCDPD=DC=BC=1AB=2AB∥DC∠BCD=900 1求证PC⊥BC 2求 sketch template

如图四棱锥P ABCD中PA⊥平面ABCD底面ABCD是直角梯形且AB∥CD∠BAD=90°PA=AD=DC=2AB=4．1 sketch template

如图在四棱锥P ABCD中底面ABCD是矩形侧棱PA垂直于底面EF分别是ABPC的中点 1求证CD⊥PD 2求证 sketch template

如图四棱锥P ABCD中PD⊥平面ABCD底面ABCD是正方形PD=AB=2E为PC中点．1求证DE⊥平面PCB2求点C sketch template

17． 如图所示在四棱锥P ABCD中∠ABC＝∠ACD＝90°∠BAC＝∠CAD＝60°PA⊥平面ABCDE为PD的中点PA sketch template

如图在四棱锥P ABCD中ABCD是菱形PA⊥平面ABCD1求证BD⊥PC2若平面PBC与平面PAD的交线为l求证BC∥ sketch template

如图四棱锥P ABCD中底面ABCD是边长为a的正方形PD=aPA=PC=a 1求证PD⊥平面ABCD 2求异面直线PB sketch template

如图在正四棱锥P ABCD中AB=PA=21求直线PA与底面ABCD所成角的大小2求点A到平面PBC的距离．题目和参考答案 sketch template

如图在底面是菱形的四棱锥 P ABCD中∠ABC=60°PA⊥平面ABCD点EFG分别为CDPDPB的中点．PA=AD=2 sketch template

如图在四棱锥P ABCD中PA⊥平面ABCD四边形ABCD为直角梯形AD//BC且AD>BC∠DAB=∠ABC=90°PA=AB sketch template

如图四棱锥P ABCD的底面ABCD是边长为2的菱形∠ABC=60°点MN分别为PBBC的中点且PA⊥平面ABCDAC与BD相交 sketch template

如图四棱锥P ABCD中底面ABCD为矩形PA⊥平面ABCDE为PD的中点．1证明PB∥平面AEC2设AP=AB=1AD sketch template

如图四棱锥P ABCD中PD⊥平面ABCD底面ABCD是正方形PD=AB=2E为PC中点．1求证DE⊥平面PCB2求点C sketch template

19．如图在四棱锥P ABCD中底面ABCD是矩形MN分别为PABC的中点 PD⊥平面ABCD且PD=AD=CD=1 1 sketch template

四棱锥 360百� sketch template

如图在四棱锥P ABCD中PA⊥底面ABCDAD∥BCAB⊥ADAC与BD交于点OPA=3AD=2AB=23BC=6．Ⅰ sketch template

如图已知四棱锥P ABCD中底面ABCD是直角梯形ABCDABC=45°DC=1AB=2PA平面ABCDPA=1 1求证 sketch template

如图在四棱锥P ABCD中底面ABCD是边长为2的正方形PA=PBPA⊥PBF为CE上的点且BF⊥平面PAC．Ⅰ求证平面 sketch template

如图所示在四棱锥S ABCD中底面ABCD是正方形侧棱SD⊥平面ABCDSD=DC点E是SC的中点作EF⊥SB交SB于点F．1 sketch template

19．已知四棱锥P ABCD的底面ABCD的边长为1的正方形 PD⊥底面ABCD且PD=1 1求证BC//平面PAD 2若 sketch template

如图四棱锥P ABCD中底面ABCD是边长为2的正方形PB⊥BCPD⊥CD且PA=2E为PD中点．1求二面角B EC A的正弦 sketch template

百度教育 sketch template

百度教育 sketch template

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